241 research outputs found
Trees in tournaments
AbstractA digraph is said to be n-unavoidable if every tournament of order n contains it as a subgraph. Let f(n) be the smallest integer such that every oriented tree is f(n)-unavoidable. Sumner (see (Reid and Wormald, Studia Sci. Math. Hungaria 18 (1983) 377)) noted that f(n)⩾2n−2 and conjectured that equality holds. Häggkvist and Thomason established the upper bounds f(n)⩽12n and f(n)⩽(4+o(1))n. Let g(k) be the smallest integer such that every oriented tree of order n with k leaves is (n+g(k))-unavoidable. Häggkvist and Thomason (Combinatorica 11 (1991) 123) proved that g(k)⩽2512k3. Havet and Thomassé conjectured that g(k)⩽k−1. We study here the special case where the tree is a merging of paths (the union of disjoint paths emerging from a common origin). We prove that a merging of order n of k paths is (n+32(k2−3k)+5)-unavoidable. In particular, a tree with three leaves is (n+5)-unavoidable, i.e. g(3)⩽5. By studying trees with few leaves, we then prove that f(n)⩽385n−6
Trees in tournaments
AbstractA digraph is said to be n-unavoidable if every tournament of order n contains it as a subgraph. Let f(n) be the smallest integer such that every oriented tree is f(n)-unavoidable. Sumner (see (Reid and Wormald, Studia Sci. Math. Hungaria 18 (1983) 377)) noted that f(n)⩾2n−2 and conjectured that equality holds. Häggkvist and Thomason established the upper bounds f(n)⩽12n and f(n)⩽(4+o(1))n. Let g(k) be the smallest integer such that every oriented tree of order n with k leaves is (n+g(k))-unavoidable. Häggkvist and Thomason (Combinatorica 11 (1991) 123) proved that g(k)⩽2512k3. Havet and Thomassé conjectured that g(k)⩽k−1. We study here the special case where the tree is a merging of paths (the union of disjoint paths emerging from a common origin). We prove that a merging of order n of k paths is (n+32(k2−3k)+5)-unavoidable. In particular, a tree with three leaves is (n+5)-unavoidable, i.e. g(3)⩽5. By studying trees with few leaves, we then prove that f(n)⩽385n−6
Channel assignment and multicolouring of the induced subgraphs of the triangular lattice
AbstractA basic problem in the design of mobile telephone networks is to assign sets of radio frequency bands (colours) to transmitters (vertices) to avoid interference. Often the transmitters are laid out like vertices of a triangular lattice in the plane. We investigate the corresponding colouring problem of assigning sets of colours of given size k to vertices of the triangular lattice so that the sets of colours assigned to adjacent vertices are disjoint. We prove here that every triangle-free induced subgraph of the triangular lattice is ⌈7k/3⌉-[k]colourable. That means that it is possible to assign to each transmitter of such a network, k bands of a set of ⌈7k/3⌉, so that there is no interference
Finding an induced subdivision of a digraph
We consider the following problem for oriented graphs and digraphs: Given an
oriented graph (digraph) , does it contain an induced subdivision of a
prescribed digraph ? The complexity of this problem depends on and on
whether must be an oriented graph or is allowed to contain 2-cycles. We
give a number of examples of polynomial instances as well as several
NP-completeness proofs
Out-degree reducing partitions of digraphs
Let be a fixed integer. We determine the complexity of finding a
-partition of the vertex set of a given digraph such
that the maximum out-degree of each of the digraphs induced by , () is at least smaller than the maximum out-degree of . We show
that this problem is polynomial-time solvable when and -complete otherwise. The result for and answers a question
posed in \cite{bangTCS636}. We also determine, for all fixed non-negative
integers , the complexity of deciding whether a given digraph of
maximum out-degree has a -partition such that the digraph
induced by has maximum out-degree at most for . It
follows from this characterization that the problem of deciding whether a
digraph has a 2-partition such that each vertex has at
least as many neighbours in the set as in , for is
-complete. This solves a problem from \cite{kreutzerEJC24} on
majority colourings.Comment: 11 pages, 1 figur
On the unavoidability of oriented trees
A digraph is {\it -unavoidable} if it is contained in every tournament of
order . We first prove that every arborescence of order with leaves
is -unavoidable. We then prove that every oriented tree of order
() with leaves is -unavoidable and
-unavoidable, and thus
-unavoidable. Finally, we prove that every
oriented tree of order with leaves is -unavoidable
- …